Question 3 (20 points, Weibull PDF): The CDF for the Weibull
distribution is given as, Fx(x) 1-ele/s)for0 β-2. where δ > 0 is a scale
parameter and β > 0 is the shape parameter. Let's assume that We define Y
X2. b) (10 Pts.) By using the PDF of X, determine() (a) (10 Pts.) By directly
using the CDF of X (without fx()), determine fy(). (c) (5 Pts.) With the help
of Matlab, plot fy ().
Data Sheet: Activity - Osmosis Name Course Date Activity Data Code Procedure I -Test Solution 1: Water Complete the tablesand questions below using your data and information found under the Background tab Data Table I Note: Difference in Final Volumes = Final Volume of Test Sol - Final Volume of Water Trial Starting Volume of Test Solution (L) Starting Volume of Water (L) Final Volume of Test Solution (L) Final Volume of Water (L) Difference in Final Volumes (L) 1 1.28 1.75 1.51 1.52 -0.01 2 1.28 2.00 1.64 1.64 0 Observations and Questions [1] Given that the final heights (and volumes) are the same for the water and test solution, what can you...
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