Skip to main content

Question: 7. A circular cam 200 mm in diameter rotates off centre with an eccentricity of 25 mm and operates the roller follower that is carried by the arm as shown in Fig. 23.35. ???200 mm +100mm- Spring 25 mm Fig. 23.35 The roller follower is held against the cam by means of an extension spring. Assuming that the force between the follower and the cam is approximately 250 N at the low position and 400 N at the high position. If the spring index is 7, find the diameter of wire, outside diameter of spring and the number of active coils. The maximum shear stress may be taken as 280 MPa. Use G 80 kN/mm2


ANSWER

Comments

  1. UnknownMarch 4, 2019 at 4:38 PM

    https://www.chegg.com/homework-help/questions-and-answers/question-three-32-marks-ighty-two-82-foreign-exchange-students-germany-arrived-namibia-tak-q34837516

    ReplyDelete
  2. UnknownApril 2, 2019 at 8:52 AM


    What voltage must be applied to a molybdenum-target tube in order that ... - Chegg
    Study app · Installed

    ReplyDelete
  3. UnknownApril 2, 2019 at 8:55 AM

    https://www.chegg.com/homework-help/questions-and-answers/voltage-must-applied-molybdenum-target-tube-order-emitted-x-rays-excite-k-fluorescent-radi-q21847781

    ReplyDelete

Post a Comment

Popular posts from this blog

Need answers for your academic questions?

Need answers for your academic questions? Ask them in the comment section below. Just type in the url link of your question in the comment section below. And get your answer ready in two formats. Hand written Screenshot We will post the answer as soon as we get them (questions) Thank you..
46 comments
Read more
Question: prove by induction 2^2 + 4^2 + 6^2 + ... + (2n)^2 = (2n)(2n+1)(2n+2)/6 ANSWER we will use induction on n base case : n=1 we have, 2^2 = 2*3*4/6 = 4 which is true inductive hypothesis let it be true for n = k i.e.,  2^2 + 4^2 + ... + (2k)^2 =   [(2k)(2k+1)(2k+2)]/6 inductive case let n = k+1 then we have 2^2 + 4^2 + .... + (2k)^2 + (2(k+1))^2 =   [(2k)(2k+1)(2k+2)]/6 + (2k+2)^2 =(2k+2)*[(2k)(2k+1)/6 + (2k+2)] =(2k+2)*[ (4k^2+2k)/6 + (12k + 12)/6 ] =(2k+2)*[ (4k^2+14k+12)/6 ] = =(2k+2)*[(2k)(2k+1)/6 + (2k+2)] =(2k+2)*[ (4k^2+2k)/6 + (12k + 12)/6 ] =(2k+2)*[ (4k^2+14k+12)/6 ] = (2k+2)*[ (4k^2 + 8k + 6k + 12)/6 ] = (2k+2)*[ (4k(k + 2) +6(k+2))/6 ] = (2k+2)*[ (4k+6)(k+2)/6 ] =  (2k+2)*[ 2 (2k+3)(k+2)/6  ] =   (2k+2)*[  (2k+3)*2*(k+2)/6  ] =   (2k+2)*[  (2k+3)(2k+4)/6  ] = [(2*(k+1))(2*(k+1)+1)(2*(k+1)+2)]/6 replacing k+1 by m, we get replacing k+1 by m, we get [(2*m)(2*m+1)(2*m+2)]/6 this completes our proof b...
12 comments
Read more

Get assignments and case studies solved...

Hey Guys! Checkout our new site, https://caseaments.blogspot.com/  , where you can get your assignments done at low rate. Just send us the assignment topic. Specify, what you all need, summary or step by step writing. Give us a dead-line and length of assignment. ( number of words) On the basis of that, you will be charged. Any subject, even you can send us case studies , and get them answered. Payment methods: PayPal Payoneer Mail us at earnwithmetoo@gmail.com with the above details for quick response. Or else, join Hangouts . email-id  earnwithmetoo@gmail.com
20 comments
Read more