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Explain the Atkinson’s model of the ‘flexible firm’. this is a university case study question please write 625 words and provide Harvard style referencing. ANSWER One of the management techniques for optimal use of human resources in an organisation is flexible firm model developed by John Atkinson's in 1984.The main idea behind this model is organising workplace using different flexibilities. Here workforce of organisation are segmented into 2 parts core (permanent employees ) and peripheral group, He identified 3 kind of flexibilities to be adopted in organisation functional, financial and numerical based on skill, job security, availability (supply in market ) etc. BASE OF MODEL * workforce segmentation Core group Peripheral group ( first and second ) * Types of flexibility Functional Financial Numerical Functional flexibility - It involves the flexible movement of employees fyon from one job to another based of production requirements which involv...

Explain the role of waivers with CMS. How do these contribute to the development of State Medicaid Plans (SPA's)? Answer question in 250 words or more and use 2-3 peer references. APA Style ANSWER When we talk about waivers usually it gives you an right not to obey certain rules that actually you had to follow in course of action. Here in case of medicaid programmes we may need to alter certain rules like area to be covered under program, type of medical service covered, eligibility of people to be served under program etc and here waivers and SAP's allows you to do so. Each states formulates the Medicaid programmes and main aim of such programme is to provide health coverage with low or free of cost to low income families, age old persons, pregnant women, handicaps (people with disabilities ) etc. Which involves investment of large amount of money, And it is contributed by state government as well as federal government, you can expect up to 50% contribution by fe...

ANSWER PROCESS PAPER Title - " Get ready to drive " Sub title - changing car's oil Date - 1/3/2019 SUMMARY OF PAPER Paper contains detailed process of changing oil of car and prepations need to be done to change oil. PROCESS 1.Check car whether it has oil or not. 2.If not take decision about going to lube for putting oil or want to do it yourself. 3.For quick service you need to go for lube. If you decide to go for lube services search for near by service provider. Move to service centre. Decide on service charge and cost of oil. Let them to do their duty. 4. If you decide putting oil to car on your own make sure that you have all hand tools needed and even the suitable oil for your car. 5. If you don't have things needed first get it ready. 6. Check how much oil car holds and which kind of oil you need for your car. * mineral oil * semi-synthetic oil * synthetic oil 7. Check for kind of oil filter. Whether car has di...

Canada vs America Is Canada context of cultural vastly different from America's? Write one paragraph ( 5 lines) answering the aforementioned. ANSWER Yes, Even though both countries share same continent they do possess some differences in cultural context. Here we need to look into difference in language, calture, norms, beliefs, idea's, perception etc. Canada comes under  high  cultural context means polite nature and they give lots of value to relations where as American comes under  low  cultural context means they are ambitious people , individualistic in nature and communicate in explicit or direct way. Canada can be viewed as mosaic of cultures but American can't be viewed as mosaic of cultures.

Using Space matrix identify and discuss strategies that Nestle can utilise based on Financial strength, environmental stability, competitive advantage and industry strength. State why you selected these strategies and the benefits to the company. ANSWER One of the basic management tool to determine the strategies to be formulated by the company is space matrix. It involves internal as well as external analysis of company and on that basis deciding which kind of strategies to formulate. It actually analysis 4 factors financial strength - cash flow, liquidity, leverage, ROI etc competitive advantage - market share,brand image, market niche,customers loyalty, product quality etc environment - demand elasticity, GDP, inflation, government regulations, technological advances etc industry strength - growth opportunities, entry barriers etc Nestle space matrix value table FACTORS VARIABLES AVERAGE RATING Finance ( 1 to 6 best being 6 ) profit after tax ( increase...

ANSWER Case 1 prior to giving final decision to any legal case court may restrain a party from continue with a course of conduct until the case has been decided here court restrained shawn fanning. case had large number of plaintiff's all members of the Recording Industry Association of America (RIAA) and they succeeded in providing that defendant had the knowledge of copyright infringement that influenced the court to take decision of injuction. Yes, I do agree with court decision because it was case related to copyright infringement which is illegal in the eye's of law. Case 2 If we consider our personal opinion it may be right on the part of ENI which argued that the regulation violated the companies first amendment right to free speech. But when we go through cyber law and right to free speech is bound by some limits same as in case of general public. Yes, because even though it's press which main duty is to provide true picture of happenings in County...

ANSWER Y(t) has autocorrelation function R Y (t,τ)=E[Y(t)Y(t+τ)] =E[X(t-t 0 )X(t+τ-t 0 )] =R x (τ) The cross correlation of X(t) and Y(t) is R XY (t,τ)=E[Y(t)Y(t+τ)] =E[X(t)X(t+τ-t 0 )] =R x (τ-t 0 )

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ANSWER ALL 4 QUESTIONS and DO NOT ROUND UP ANSWER Given , 14% = 0.14 5 day work week a. on monday and again on tuesday, continuous 2 days, so multiply 2 times 0.14 * 0.14 =  0.0196 b. for the first time on thursday (100% - 14% = 86%, 86% = 0.86) monday to wednesday and on thursday 0.86 * 0.86 * 0.86 * 0.14 =  0.089 c. every day 5 work days, monday to friday, so, multiply 5 times (0.14)^5 =  0.00005378 d. at least once during the week 1 - P(not stopped) = 1 - 0.86^5 = 1 - 0.4704270176 =  0.5295

You have samples of various sizes which you use to estimate a population mean. In the population, the true mean is 100 and the true standard deviation is 10. With which of the following sample sizes are you most likely to see an estimated mean of 135? a) Sample size 2 b) Sample size 1 c) Sample size 10 d) Sample size 100 ANSWER Given, In the population, the true mean = 100 the true standard deviation = 10. With estimated mean of 135, sample size can be 101, almost nearer to, d. Sample size 100 n = N*X / (N + X – 1), where, X = Zα/2 2  ­* σ 2  / MOE 2 , and Zα/2 is the critical value of the Normal distribution at α/2 (e.g. for a confidence level of 95%, α is 0.05 and the critical value is 1.96), MOE is the margin of error, σ 2  is the population variance, and N is the population size. 

ANSWER c) P(S)  = P(S|L,F)P(L)P(F)+P(S|~L,F)P(~L)P(F)+           P(S|L,~F)P(L)P(~F)+P(S|~L,~F)P(~L)P(~F)        = 0.4*0.6*0.8+0.6*0.6*0.5+0.4*0.4*0.6+0.6*0.4*0.3       = 0.54 d) P(S|A) = P(S,A) / [P(A|S)P(S)+P(A|~S)P(~S)] = (0.54*0.7)/(0.54*0.7+0.46*0.3) = 0.733

ANSWER Interpretation of the {ai} as transition rates; the transition rate matrix (infinitesimal generator) Q Assume here that Pi,i = 0 for all i ∈ S. ai can be interpreted as the transition rate out of state i given that X(t) = i; the intuitive idea being that the exponential holding time will end, independent of the past, in the next dt units of time with probability aidt. This can be made rigorous recalling the little o(t) results for the Poisson process: Let {Ni(t)} denote a Poisson counting process at rate ai . Then P(Ni(h) > 0) = aih + o(h) and P(Ni(h) = 1) = aih + o(h) (and P(Ni(h) > 1) = o(h)). Thus lim h↓0 P(X(h) ≠ i | X(0) = i)/h = lim h↓0 P(Ni(h) = 1)/h = lim h↓0 (aih + o(h))/h = ai …….. (1) More generally, for j ≠i, we additionally use the Markov property asserting that once leaving state i the chain will, independent of the past, next go to state j with probability Pi,j to obtain P’ i,j (0) = lim h↓0 Pi,j (h)/h = lim h↓0 P(Ni(h) = 1)Pi,j/h = aiPi,...